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Balance equation of any chemical reaction online for free
C2H5F + F2 = C2H4F2 + HF => C2H5F + F2 = C2H4F2 + HF
CH2O + [Ag(NH3)2]OH = HCOONH4 + Ag + NH3 + H2O => CH2O + 2[Ag(NH3)2]OH = HCOONH4 + 2 Ag + 3 NH3 + H2O
BaO2 = BaO + O2 => 2 BaO2 = 2 BaO + O2
AgCl + NaOH = AgOH + NaCl => AgCl + NaOH = AgOH + NaCl
CO2 + KOH = K2CO3 + H2O => CO2 + 2 KOH = K2CO3 + H2O
C2H5F + F2 = C2H4F2 + HF => C2H5F + F2 = C2H4F2 + HF
SCl2 + NaF = SF4 + S2Cl2 + NaCl => 3 SCl2 + 4 NaF = SF4 + S2Cl2 + 4 NaCl
K + Br2 = KBr => 2 K + Br2 = 2 KBr
Mg3N2 + H2O = Mg(OH)2 + NH3 => Mg3N2 + 6 H2O = 3 Mg(OH)2 + 2 NH3
CO2 + H2O = C6H12O6 + O2 => 6 CO2 + 6 H2O = C6H12O6 + 6 O2
CaCO3 = CaO + CO2 => CaCO3 = CaO + CO2
CH4 + F2 = CF4 + HF => CH4 + 4 F2 = CF4 + 4 HF
Fe2O3 + CO = Fe + CO2 => Fe2O3 + 3 CO = 2 Fe + 3 CO2
AgCl + HNO3 = AgNO3 + HCl => AgCl + HNO3 = AgNO3 + HCl
H2O2 = H2O + O2 => 2 H2O2 = 2 H2O + O2
AgCl + HNO3 = AgNO3 + HCl => AgCl + HNO3 = AgNO3 + HCl
H3PO4 + NH3 = (NH4)3PO4 => H3PO4 + 3 NH3 = (NH4)3PO4
MnO3 + H2O = H2MnO4 => MnO3 + H2O = H2MnO4
KH2PO4 + NaH4PO5 + CuO = KNaCuP2O7 + H2O => KH2PO4 + NaH4PO5 + CuO = KNaCuP2O7 + 3 H2O
CH4 + O2 = CO2 + H2O => CH4 + 2 O2 = CO2 + 2 H2O
CH4 + O2 = CO2 + H2O => CH4 + 2 O2 = CO2 + 2 H2O
C4H10 + O2 = CO2 + H2O => 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
Al + HCl = AlCl3 + H2 => 2 Al + 6 HCl = 2 AlCl3 + 3 H2
KClO3 = KCl + O2 => 2 KClO3 = 2 KCl + 3 O2
Na + Cl2 = NaCl => 2 Na + Cl2 = 2 NaCl
AgNO3 + CaCl2 = AgCl + Ca(NO3)2 => 2 AgNO3 + CaCl2 = 2 AgCl + Ca(NO3)2
H2 + O2 = H2O => 2 H2 + O2 = 2 H2O
Fe2S3 + HCl = FeCl3 + H2S => Fe2S3 + 6 HCl = 2 FeCl3 + 3 H2S
C6H11C6H5 + Br2 = BrC6H10C6H5 + HBr => C6H11C6H5 + Br2 = BrC6H10C6H5 + HBr
AgNO3 + CaCl2 = AgCl + Ca(NO3)2 => 2 AgNO3 + CaCl2 = 2 AgCl + Ca(NO3)2
PbC8H20 + O2 = PbO2 + CO2 + H2O => PbC8H20 + 14 O2 = PbO2 + 8 CO2 + 10 H2O
PbC8H20 + O2 = PbO2 + CO2 + H2O => PbC8H20 + 14 O2 = PbO2 + 8 CO2 + 10 H2O
C2H4 + O2 = CO2 + H2O => C2H4 + 3 O2 = 2 CO2 + 2 H2O
S8 + O2 = SO3 => S8 + 12 O2 = 8 SO3
Al + O2 = Al2O3 => 4 Al + 3 O2 = 2 Al2O3
Sr + Dy + La + Pr + Nd + Ti + O = Sr6125Dy125La1250Pr1250Nd1250Ti10000O30000 => 6125 Sr + 125 Dy + 1250 La + 1250 Pr + 1250 Nd + 10000 Ti + 30000 O = Sr6125Dy125La1250Pr1250Nd1250Ti10000O30000
KClO3 = KClO4 + KCl => 4 KClO3 = 3 KClO4 + KCl
HgO = Hg + O2 => 2 HgO = 2 Hg + O2
N2O5 + H2O = HNO3 => N2O5 + H2O = 2 HNO3
HCl + NaOH = NaCl + H2O => HCl + NaOH = NaCl + H2O
Ag3N + H2O = NH3 + Ag2O => 2 Ag3N + 3 H2O = 2 NH3 + 3 Ag2O
NH4Cl + Ba(OH)2 = NH3 + BaCl2 + H2O => 2 NH4Cl + Ba(OH)2 = 2 NH3 + BaCl2 + 2 H2O
N2 + H2 = NH3 => N2 + 3 H2 = 2 NH3
Zn + HCl = ZnCl2 + H2 => Zn + 2 HCl = ZnCl2 + H2
CH3F + Cl2 = CCl3F + HCl => CH3F + 3 Cl2 = CCl3F + 3 HCl
H + O = H2O => 2 H + O = H2O
Li(s) + CaF2(aq) = Ca(s) + LiF(aq) => 2 Li(s) + CaF2(aq) = Ca(s) + 2 LiF(aq)
CO2 + H2 = CO + H2O => CO2 + H2 = CO + H2O
Ba + Na2 = BaNa2 => Ba + Na2 = BaNa2
Ca3(PO4)2 + SiO2 + C = CaSiO3 + P4 + CO => 2 Ca3(PO4)2 + 6 SiO2 + 10 C = 6 CaSiO3 + P4 + 10 CO
Balance equation of any chemical reaction online for freeEquations balanced on 01/13/20 Equations balanced on 12/21/19 Equations balanced on 01/20/19 사이트를 이용하면, 이용 약관과 개인정보취급방침에 동의한 것으로 간주합니다. © 2021 webqc.org All rights reserved
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