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Balance equation of any chemical reaction online for free
SiO2 + H2O = H2SiO3 => SiO2 + H2O = H2SiO3
B2Br6 + HNO3 = B(NO3)3 + HBr => B2Br6 + 6 HNO3 = 2 B(NO3)3 + 6 HBr
(NH4)3PO4 + CaBr2 = Ca3(PO4)2 + NH4Br => 2(NH4)3PO4 + 3 CaBr2 = Ca3(PO4)2 + 6 NH4Br
Pb(ClO3)4 + KOH = Pb(OH)4 + KClO3 => Pb(ClO3)4 + 4 KOH = Pb(OH)4 + 4 KClO3
PbCl2 + K2CrO4 = PbCrO4 + KCl => PbCl2 + K2CrO4 = PbCrO4 + 2 KCl
C2H6 + O2 = CO2 + H2O => 2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
KBr + Fe(OH)3 = KOH + FeBr3 => 3 KBr + Fe(OH)3 = 3 KOH + FeBr3
Sn + HCl = SnCl4 + H2 => Sn + 4 HCl = SnCl4 + 2 H2
C6H6 + O2 = CO2 + H2O => 2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
K + H2O = KOH + H2 => 2 K + 2 H2O = 2 KOH + H2
FeS2 + O2 = Fe2O3 + SO2 => 4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2
C3H8 + O2 = CO + H2O => 2 C3H8 + 7 O2 = 6 CO + 8 H2O
N2 + H2 = NH3 => N2 + 3 H2 = 2 NH3
Fe3O4 + O2 = Fe2O3 => 4 Fe3O4 + O2 = 6 Fe2O3
FeCl3 + NaOH = Fe(OH)3 + NaCl => FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl
N2 + H2 = NH3 => N2 + 3 H2 = 2 NH3
Pb(NO3)2 + KI = PbI2 + KNO3 => Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3
CaCO3 = CaO + CO2 => CaCO3 = CaO + CO2
Na + Cl2 = NaCl => 2 Na + Cl2 = 2 NaCl
BaCl2 + H2SO4 = BaSO4 + HCl => BaCl2 + H2SO4 = BaSO4 + 2 HCl
Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O => 2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
Cu + AgCH3COO = Cu(CH3COO)2 + Ag => Cu + 2 AgCH3COO = Cu(CH3COO)2 + 2 Ag
Ba(OH)2 + H2SO4 = BaSO4 + H2O => Ba(OH)2 + H2SO4 = BaSO4 + 2 H2O
KClO3 = KCl + O2 => 2 KClO3 = 2 KCl + 3 O2
(NH4)2SO4 + BaCl2 = NH4Cl + BaSO4 => (NH4)2SO4 + BaCl2 = 2 NH4Cl + BaSO4
HgO = Hg + O2 => 2 HgO = 2 Hg + O2
P4O10 + H2O = H3PO4 => P4O10 + 6 H2O = 4 H3PO4
PbS + H2O2 = PbSO4 + H2O => PbS + 4 H2O2 = PbSO4 + 4 H2O
NH3 + O2 + CH4 = HCN + H2O => 2 NH3 + 3 O2 + 2 CH4 = 2 HCN + 6 H2O
KO2 + CO2 = K2CO3 + O2 => 4 KO2 + 2 CO2 = 2 K2CO3 + 3 O2
AlBr3 + Cl2 = AlCl3 + Br2 => 2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
C2H6 + O2 = CO2 + H2O => 2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
CS + O2 = CO2 + SO2 => CS + 2 O2 = CO2 + SO2
C2H6 + O2 = CO + H2O => 2 C2H6 + 5 O2 = 4 CO + 6 H2O
KClO3 = KCl + O2 => 2 KClO3 = 2 KCl + 3 O2
C2H6 + O2 = CO + H2O => 2 C2H6 + 5 O2 = 4 CO + 6 H2O
CaO + P4O10 = Ca3(PO4)2 => 6 CaO + P4O10 = 2 Ca3(PO4)2
C4H8 + O2 = CO2 + H2O => C4H8 + 6 O2 = 4 CO2 + 4 H2O
C4H10 + O2 = CO2 + H2O => 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
Fe + Sn(NO3)4 = Fe(NO3)3 + Sn => 4 Fe + 3 Sn(NO3)4 = 4 Fe(NO3)3 + 3 Sn
C4H8 + O2 = CO2 + H2O => C4H8 + 6 O2 = 4 CO2 + 4 H2O
BF3 + Li2SO3 = B2(SO3)3 + LiF => 2 BF3 + 3 Li2SO3 = B2(SO3)3 + 6 LiF
Ba(NO3)2 + Na2SO4 = BaSO4 + NaNO3 => Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3
KClO3 = KCl + O2 => 2 KClO3 = 2 KCl + 3 O2
Cu + HNO3 = Cu(NO3)2 + NO + H2O => 3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O
Mg3N2 + H2O = Mg(OH)2 + NH3 => Mg3N2 + 6 H2O = 3 Mg(OH)2 + 2 NH3
C6H5COOH + O2 = CO2 + H2O => 2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O
Mg + HCl = MgCl2 + H2 => Mg + 2 HCl = MgCl2 + H2
C3H8 + O2 = CO2 + H2O => C3H8 + 5 O2 = 3 CO2 + 4 H2O
C4H10 + O2 = CO2 + H2O => 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
Balance equation of any chemical reaction online for freeEquations balanced on 01/13/20 Equations balanced on 12/21/19 Equations balanced on 01/20/19 사이트를 이용하면, 이용 약관과 개인정보취급방침에 동의한 것으로 간주합니다. © 2021 webqc.org All rights reserved
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