Equations balanced on the previous day | Equations balanced on the next day |
15 I2 + 16 OH{-} = 8 H2O + 26 I{-} + 2 O4I2{5+}
Ba(NO3)2 + La(NO3)3*6H2O + NH4H2PO4 + NH2CONH2 = Ba3La(PO4)3 + CO2 + N2 + H2O =>
3 Ba(NO3)2 + La(NO3)3*6H2O + 3 NH4H2PO4 + 6 NH2CONH2 = Ba3La(PO4)3 + 6 CO2 + 12 N2 + 27 H2O
C2HO2ClCa + C4H13N3 + NaOH + H2O = C14H23N3O10 + Ca(OH)2 + NaCl =>
5 C2HO2ClCa + C4H13N3 + 5 NaOH + 5 H2O = C14H23N3O10 + 5 Ca(OH)2 + 5 NaCl
HCl(aq) + MnO2(s) = MnCl2 + H2O(l) + Cl2(g) =>
4 HCl(aq) + MnO2(s) = MnCl2 + 2 H2O(l) + Cl2(g)
MnO2(s) + HCl(aq) = MnCl2 + H2O + Cl2(g) =>
MnO2(s) + 4 HCl(aq) = MnCl2 + 2 H2O + Cl2(g)
KC2H3O2 + H2SO4 = KSO4 + H2C2H3O2 =>
KC2H3O2 + H2SO4 = KSO4 + H2C2H3O2
Na + Cl + O + H2O = NaClH2O2 =>
Na + Cl + O + H2O = NaClH2O2
KCl + Fe2(SO4)3 + H2O = KClO3 + FeSO4 + H2SO4 =>
KCl + 3 Fe2(SO4)3 + 3 H2O = KClO3 + 6 FeSO4 + 3 H2SO4
NaO + H2O = NaOH + O2 =>
4 NaO + 2 H2O = 4 NaOH + O2
N + O2 = NO2 =>
N + O2 = NO2
Fe(OH)3 + HNO3 + K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + KNO3 + H2O =>
4 Fe(OH)3 + 12 HNO3 + 3 K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + 12 KNO3 + 12 H2O
B2S3(g) + H2O(l) = H3BO3(aq) + H2S =>
B2S3(g) + 6 H2O(l) = 2 H3BO3(aq) + 3 H2S
Sn + IO3{-} + H2O = Sn{2+} + I{-} + OH{-} =>
3 Sn + IO3{-} + 3 H2O = 3 Sn{2+} + I{-} + 6 OH{-}
NaHCO3 = Na2CO3 + CO2 + H2O =>
2 NaHCO3 = Na2CO3 + CO2 + H2O
N + O2 = NO2 =>
N + O2 = NO2
NO3{-} + Cu + H{+} = NO + Cu{3+} + H2O =>
NO3{-} + Cu + 4 H{+} = NO + Cu{3+} + 2 H2O
FeCl + Cl2O3 = Cl2 + FeO =>
6 FeCl + 2 Cl2O3 = 5 Cl2 + 6 FeO
As2S5 + H2O + HNO3 = H2SO4 + H3AsO4 + NO =>
3 As2S5 + 4 H2O + 40 HNO3 = 15 H2SO4 + 6 H3AsO4 + 40 NO
NaOH + NH4HCO3 = Na2CO3 + NH3 + H2O =>
2 NaOH + NH4HCO3 = Na2CO3 + NH3 + 2 H2O
I2 + KBr = BrI + K =>
I2 + 2 KBr = 2 BrI + 2 K
Na2Cr2O7 + C = Cr2O3 + Na2CO3 + CO =>
Na2Cr2O7 + 2 C = Cr2O3 + Na2CO3 + CO
Sr + H2O(g) = Sr(OH)2 + H2 =>
Sr + 2 H2O(g) = Sr(OH)2 + H2
Ka + AnNO3 = Ka(NO3)2 + An =>
Ka + 2 AnNO3 = Ka(NO3)2 + 2 An
K2(CD(CN)4) + S = K2S + (CD(CN)4) =>
K2(CD(CN)4) + S = K2S + (CD(CN)4)
Mg3(PO4)2 + H2SO4 = MgSO4 + H3PO4 =>
Mg3(PO4)2 + 3 H2SO4 = 3 MgSO4 + 2 H3PO4
As(OH)3 + H2SO4 = As2(SO4)3 + H2O =>
2 As(OH)3 + 3 H2SO4 = As2(SO4)3 + 6 H2O
LiCl + F = LiF + Cl2 =>
2 LiCl + 2 F = 2 LiF + Cl2
Ca(OH)2 + NH4NO2 = CaNO2 + NH3 + H2O =>
6 Ca(OH)2 + 5 NH4NO2 = 6 CaNO2 + 4 NH3 + 10 H2O
CaHCO3 + HNO3 = CaNO3 + H2O + CO2 =>
CaHCO3 + HNO3 = CaNO3 + H2O + CO2
(CO3)3Cr2 = Cr2O3 + CO2 =>
(CO3)3Cr2 = Cr2O3 + 3 CO2
H3PO4 + Ca(OH)2 = Ca(PO4) + H + (HO)2 =>
H3PO4 + Ca(OH)2 = Ca(PO4) + 3 H + (HO)2
Fe + NaOH = Fe(OH) + Na =>
Fe + NaOH = Fe(OH) + Na
CH3CH2CHO + AgNO3 + NaOH = CH3CH2COOH + Ag + H2O + NaNO3 =>
CH3CH2CHO + 2 AgNO3 + 2 NaOH = CH3CH2COOH + 2 Ag + H2O + 2 NaNO3
Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2
HIO4 + Cd(OH)2 = Cd(IO4)2 + H2O =>
2 HIO4 + Cd(OH)2 = Cd(IO4)2 + 2 H2O
CuSO4 + Al = (Al)2(SO4)3 + Cu =>
3 CuSO4 + 2 Al = (Al)2(SO4)3 + 3 Cu
Potassiumchlorate = potassiumperchlorate + Potassiumchloride =>
4 KClO3 = 3 KClO4 + KCl
Ba{2+} + NaOH = Ba(OH)2 + Na{+} =>
Ba{2+} + 2 NaOH = Ba(OH)2 + 2 Na{+}
NH3 + O2 = N2O3 + H4O =>
8 NH3 + 9 O2 = 4 N2O3 + 6 H4O
HCOOH + C3H7OH = C3H7COOC3H7 + H2O =>
HCOOH + 2 C3H7OH = C3H7COOC3H7 + 2 H2O
K2CO3 + C20H14O4 = K2CO3C20H14O4 =>
K2CO3 + C20H14O4 = K2CO3C20H14O4
Pb(NO3)2 + NaI = PbI2 + Na2(NO3)2 =>
Pb(NO3)2 + 2 NaI = PbI2 + Na2(NO3)2
FeCl3 + NaNO3 = Fe(NO3)3 + NaCl =>
FeCl3 + 3 NaNO3 = Fe(NO3)3 + 3 NaCl
PbOH2 = Pb02 + H2O =>
2 PbOH2 = Pb02 + 2 H2O
KIO3 + Al + HCl = I2 + AlCl3 + KCl + H2O =>
6 KIO3 + 10 Al + 36 HCl = 3 I2 + 10 AlCl3 + 6 KCl + 18 H2O
Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2
N2 + NaOH + H2O = NaNO3 + H2 =>
N2 + 2 NaOH + 4 H2O = 2 NaNO3 + 5 H2
NH4OH + NH4Cl + H2O = N2H11Cl + O3 =>
3 NH4OH + 3 NH4Cl + 3 H2O = 3 N2H11Cl + 2 O3
CO{2+} + Cr2O7{-2} + H{+} = CO{3+} + Cr{3+} + H2O =>
6 CO{2+} + Cr2O7{-2} + 14 H{+} = 6 CO{3+} + 2 Cr{3+} + 7 H2O
RbOH + HBr = RbBr + H2O =>
RbOH + HBr = RbBr + H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/04/23
Equations balanced on 01/03/23
저희 화학반응식 계산기에 만족하셨다면 만족도 평가를 남겨주세요