Equations balanced on the previous day | Equations balanced on the next day |
CaCO3 = CO2 + CaO
PCl5 + H2O = HCl + H3PO4 =>
PCl5 + 4 H2O = 5 HCl + H3PO4
K2CrO4 + H2SO4 = K2SO4 + CrSO4 + H2O + O2 =>
K2CrO4 + 2 H2SO4 = K2SO4 + CrSO4 + 2 H2O + O2
CH4 + H2O = H2 + CO =>
CH4 + H2O = 3 H2 + CO
FeCO3(s) + H2SO4(aq) = FeSO4 + H2O + CO2 =>
FeCO3(s) + H2SO4(aq) = FeSO4 + H2O + CO2
C7H6O(aq) + KMnO4(aq) = KCO(aq) + Mn(aq) + H2O(l) + CO2 =>
5 C7H6O(aq) + 16 KMnO4(aq) = 16 KCO(aq) + 16 Mn(aq) + 15 H2O(l) + 19 CO2
Pb(C2H3O2)2 + KI = PbI2 + K + CO + H =>
Pb(C2H3O2)2 + 2 KI = PbI2 + 2 K + 4 CO + 6 H
HClO(aq) + Ca(OH)2(aq) = H2O(l) + Ca(ClO)2 =>
2 HClO(aq) + Ca(OH)2(aq) = 2 H2O(l) + Ca(ClO)2
PbCl2 + NaCl = PbCl2*NaCl =>
PbCl2 + NaCl = PbCl2*NaCl
AgOH + C6H12O6 = Ag + H2O + CO2 =>
24 AgOH + C6H12O6 = 24 Ag + 18 H2O + 6 CO2
KCO3 + MgCl = KCl + MgCO3 =>
KCO3 + MgCl = KCl + MgCO3
VO + H2O = V(OH)4 + H3O =>
VO + 5 H2O = V(OH)4 + 2 H3O
C2H2 + Br2 = C2H2Br2 =>
C2H2 + Br2 = C2H2Br2
CH3COONa + Ca(OH)2 = CaO + CH3COOH + Na2CO3 + CH4 =>
2 CH3COONa + Ca(OH)2 = CaO + CH3COOH + Na2CO3 + CH4
KMnO4 + H2SO4 + C2H6O = K2SO4 + MnO2 + CO2 + H2O =>
4 KMnO4 + 2 H2SO4 + C2H6O = 2 K2SO4 + 4 MnO2 + 2 CO2 + 5 H2O
KCl + Na2SnO3 = KClO3 + Na2SnO2 =>
KCl + 3 Na2SnO3 = KClO3 + 3 Na2SnO2
AsO3{-3} + MnO4{-} + H{+} = AsO4{-3} + Mn{+2} + H2O =>
5 AsO3{-3} + 2 MnO4{-} + 6 H{+} = 5 AsO4{-3} + 2 Mn{+2} + 3 H2O
Ni + AgSO{4} = Ag + NiSO{4} =>
Ni + AgSO{4} = Ag + NiSO{4}
Ba(CO3) + CH3COOH = H2O + CO2 + Ba(C2H3O2)2 =>
Ba(CO3) + 2 CH3COOH = H2O + CO2 + Ba(C2H3O2)2
NiSO4 + NaOH = Na2 + SO4 + Ni(OH)2 =>
NiSO4 + 2 NaOH = Na2 + SO4 + Ni(OH)2
CH3(g) + O2(g) = CO2(g) + H2O(g) =>
4 CH3(g) + 7 O2(g) = 4 CO2(g) + 6 H2O(g)
FeCl3 + NH3 = [Fe(NH3)]3 + Cl =>
3 FeCl3 + 3 NH3 = [Fe(NH3)]3 + 9 Cl
C10H20O3 + O2 = CO2 + H2O =>
2 C10H20O3 + 27 O2 = 20 CO2 + 20 H2O
Bi(NO3)3 + Mg = Bi + Mg(NO3)2 =>
2 Bi(NO3)3 + 3 Mg = 2 Bi + 3 Mg(NO3)2
Zr(OH)4 + H2SO4 = (ZrOH)2(SO4)3 + H2O =>
2 Zr(OH)4 + 3 H2SO4 = (ZrOH)2(SO4)3 + 6 H2O
Mg(OH)2 + NH3 + NaH2PO4 = MgNH4PO4 + NaOH + H2O =>
Mg(OH)2 + NH3 + NaH2PO4 = MgNH4PO4 + NaOH + H2O
HNO3 + KOH = K{+} + NO3{-} + H2O =>
HNO3 + KOH = K{+} + NO3{-} + H2O
CrBr3 + I2 + LiOH = Li2CrO4 + LiBrO3 + LiI + H2O =>
2 CrBr3 + 21 I2 + 52 LiOH = 2 Li2CrO4 + 6 LiBrO3 + 42 LiI + 26 H2O
H2SO4 + K4Fe(CN)6 + KMnO4 = CO2 + Fe2(SO4)3 + H2O + HNO3 + KHSO4 + MnSO4 =>
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122 MnSO4
CH3CO2HNaOH = H2ONaCH3CO2 =>
CH3CO2HNaOH = H2ONaCH3CO2
CH2CH3CH2 + O2 = CO2 + H2O =>
4 CH2CH3CH2 + 19 O2 = 12 CO2 + 14 H2O
C4H10 + O62 = CO2 + H2O =>
62 C4H10 + 13 O62 = 248 CO2 + 310 H2O
Mg + Cl2 = MgCl2 =>
Mg + Cl2 = MgCl2
BaCl2*2H2O + TiCl4 + NaOH = BaTiO3 + NaCl + H2O =>
BaCl2*2H2O + TiCl4 + 6 NaOH = BaTiO3 + 6 NaCl + 5 H2O
RSH + Au = RSAu + H2 =>
2 RSH + 2 Au = 2 RSAu + H2
[Cu(CH3COO)2] + H2O = Cu + CH3COOH + O =>
[Cu(CH3COO)2] + H2O = Cu + 2 CH3COOH + O
NaHCO3 + H2O = NaOH + H2CO3 =>
NaHCO3 + H2O = NaOH + H2CO3
PbI + KNO3 + O2 = PbO2 + KI + NO3 =>
PbI + KNO3 + O2 = PbO2 + KI + NO3
FeSO + KClO3 + H2SO4 = Fe(SO4)3 + KCl + H2O =>
3 FeSO + 5 KClO3 + 6 H2SO4 = 3 Fe(SO4)3 + 5 KCl + 6 H2O
NH3(aq) + CuSO4(aq) = Cu(NH3)4SO4(s) =>
4 NH3(aq) + CuSO4(aq) = Cu(NH3)4SO4(s)
C3H8O + O2 = CO2 + H2O =>
2 C3H8O + 9 O2 = 6 CO2 + 8 H2O
VO2{+} + Mn{2+} + H{+} = VO{2+} + MnO4{-} + H2O =>
5 VO2{+} + Mn{2+} + 2 H{+} = 5 VO{2+} + MnO4{-} + H2O
Al(NO3)3 + LiOH = Li(NO3) + Al(OH)3 =>
Al(NO3)3 + 3 LiOH = 3 Li(NO3) + Al(OH)3
Ni(SCN)2 + Ca(ClO)2 = Ni(ClO)2 + Ca(SCN)2 =>
Ni(SCN)2 + Ca(ClO)2 = Ni(ClO)2 + Ca(SCN)2
HSiCl3 + H2O = H10Si10O15 + HCl =>
10 HSiCl3 + 15 H2O = H10Si10O15 + 30 HCl
Zn + Li2CO3 = ZnCO3 + Li =>
Zn + Li2CO3 = ZnCO3 + 2 Li
C6H5 + HBr = C6H6 + Br2 =>
2 C6H5 + 2 HBr = 2 C6H6 + Br2
Zn + HCl = ZnCl2Cl + H2 =>
2 Zn + 6 HCl = 2 ZnCl2Cl + 3 H2
HCl + Ni = ClNi + H2 =>
2 HCl + 2 Ni = 2 ClNi + H2
CaCO3 + HCl = CO2 + CaCl2 + H2O =>
CaCO3 + 2 HCl = CO2 + CaCl2 + H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/04/23
Equations balanced on 01/03/23
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