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Chemical Equations Balanced on 12/28/19

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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Zn + Fe(NO3)3 = Fe + Zn(NO3)2 =>
3 Zn + 2 Fe(NO3)3 = 2 Fe + 3 Zn(NO3)2

Zn + Pb(NO3)2 = Zn(NO3)2 + Pb =>
Zn + Pb(NO3)2 = Zn(NO3)2 + Pb

H2SO4 + HI = H2S + I2 + H2O =>
H2SO4 + 8 HI = H2S + 4 I2 + 4 H2O

Fe2(SO4)3 + NaOH = Fe(OH)3 + Na2SO4 =>
Fe2(SO4)3 + 6 NaOH = 2 Fe(OH)3 + 3 Na2SO4

NH3 + NO = N2 + H2O =>
4 NH3 + 6 NO = 5 N2 + 6 H2O

Zn + Cu(NO3)2 = Zn(NO3)2 + Cu =>
Zn + Cu(NO3)2 = Zn(NO3)2 + Cu

Pb + Cu(NO3)2 = Pb(NO3)2 + Cu =>
Pb + Cu(NO3)2 = Pb(NO3)2 + Cu

NH4NO3 + KOH = KNO3 + NH3 + H2O =>
NH4NO3 + KOH = KNO3 + NH3 + H2O

Fe + Pb(NO3)2 = Fe(NO3)2 + Pb =>
Fe + Pb(NO3)2 = Fe(NO3)2 + Pb

Al + Cu(NO3)2 = Al(NO3)3 + Cu =>
2 Al + 3 Cu(NO3)2 = 2 Al(NO3)3 + 3 Cu

Fe + Ni(NO3)2 = Fe(NO3)3 + Ni =>
2 Fe + 3 Ni(NO3)2 = 2 Fe(NO3)3 + 3 Ni

HNO3 + Mg(OH)2 = Mg(NO3)2 + H2O =>
2 HNO3 + Mg(OH)2 = Mg(NO3)2 + 2 H2O

FeS + HCl = FeCl2 + H2S =>
FeS + 2 HCl = FeCl2 + H2S

KClO3 + FeSO4 + H2SO4 = KCl + Fe2(SO4)3 + H2O =>
KClO3 + 6 FeSO4 + 3 H2SO4 = KCl + 3 Fe2(SO4)3 + 3 H2O

H2S + H2O2 = SO2 + H2O =>
H2S + 3 H2O2 = SO2 + 4 H2O

K2Cr2O7 + HCl = KCl + CrCl3 + Cl3 + H2O =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 2 Cl3 + 7 H2O

MgSO3 = Mg + SO3 =>
MgSO3 = Mg + SO3

MnO2 + HCl = MnCl2 + H2O + Cl2 =>
MnO2 + 4 HCl = MnCl2 + 2 H2O + Cl2

H2O2 + Cr(OH)6{-3} = OH{-} + CrO4{-2} + H2O =>
3 H2O2 + 2 Cr(OH)6{-3} = 2 OH{-} + 2 CrO4{-2} + 8 H2O

Cu + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

Cu + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

H3PO3 + Mg(OH)2 = Mg3(PO3)2 + H2O =>
2 H3PO3 + 3 Mg(OH)2 = Mg3(PO3)2 + 6 H2O

Cu + HCl = CuCl2 + H2 =>
Cu + 2 HCl = CuCl2 + H2

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Ag + HNO3 = Ag(NO3) + NO2 + H2O =>
Ag + 2 HNO3 = Ag(NO3) + NO2 + H2O

PH3 + KOH + K2[PdCl4] = P4 + Pd + KCl + H2O =>
4 PH3 + 12 KOH + 6 K2[PdCl4] = P4 + 6 Pd + 24 KCl + 12 H2O

Al4C3 + H2O = CH4 + Al(OH)3 =>
Al4C3 + 12 H2O = 3 CH4 + 4 Al(OH)3

C6H5CH3CH3 + KMnO4 + KOH = C6H5COOK + K2MnO4 + H2O =>
7 C6H5CH3CH3 + 61 KMnO4 + 69 KOH = 8 C6H5COOK + 61 K2MnO4 + 53 H2O

Ag + HNO3 = Ag(NO3) + NO + H2O =>
3 Ag + 4 HNO3 = 3 Ag(NO3) + NO + 2 H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

C6H5CH2CH3 + KMnO4 + KOH = C6H5COOK + K2MnO4 + H2O =>
7 C6H5CH2CH3 + 54 KMnO4 + 62 KOH = 8 C6H5COOK + 54 K2MnO4 + 46 H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

H2SO4 = H2O + O2 + SO2 =>
2 H2SO4 = 2 H2O + O2 + 2 SO2

CaO + CO2 = CaCO3 =>
CaO + CO2 = CaCO3

CaO + CO2 = CaCO3 =>
CaO + CO2 = CaCO3

CaO + CO2 = CaCO3 =>
CaO + CO2 = CaCO3

K2CrO7 + FeSO4 + H2SO4 = Cr(SO4)3 + Fe(SO4)3 + K2SO4 + H2O =>
2 K2CrO7 + 3 FeSO4 + 14 H2SO4 = 2 Cr(SO4)3 + 3 Fe(SO4)3 + 2 K2SO4 + 14 H2O

CuSO4 + NH3 + H2O = (NH4)2SO4 + Cu(NH3)4(OH)2 =>
CuSO4 + 6 NH3 + 2 H2O = (NH4)2SO4 + Cu(NH3)4(OH)2

CuSO4 + NH3 + H2O = (NH4)2SO4 + Cu(NH3)4(OH)2 =>
CuSO4 + 6 NH3 + 2 H2O = (NH4)2SO4 + Cu(NH3)4(OH)2

MnO4{-} + C2O4{2-} + H{+} = Mn{2+} + CO2 + H2O =>
2 MnO4{-} + 5 C2O4{2-} + 16 H{+} = 2 Mn{2+} + 10 CO2 + 8 H2O

IO3{-} + AsO3{3-} = I{-} + AsO4{3-} =>
IO3{-} + 3 AsO3{3-} = I{-} + 3 AsO4{3-}

MnO4{-} + NO2{-} + H2O = MnO2 + NO3{-} + OH{-} =>
2 MnO4{-} + 3 NO2{-} + H2O = 2 MnO2 + 3 NO3{-} + 2 OH{-}

CuSO4 + NaOH = Cu(OH)2 + Na2SO4 =>
CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4

Ag2S = Ag + S8 =>
8 Ag2S = 16 Ag + S8

Ag2S = Ag + S =>
Ag2S = 2 Ag + S

K2Cr2O7 + HCl = KCl + CrCl3 + H2O + Cl2 =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 7 H2O + 3 Cl2

Cu + HCl = CuCl2 + H2 =>
Cu + 2 HCl = CuCl2 + H2

NH4OH + HCl = NH4Cl + H2O =>
NH4OH + HCl = NH4Cl + H2O

HCl + CaCO3 = CaCl2 + H2O + CO2 =>
2 HCl + CaCO3 = CaCl2 + H2O + CO2

Na2O + H2O = NaOH =>
Na2O + H2O = 2 NaOH

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/21/19
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