Equations balanced on the previous day | Equations balanced on the next day |
9 H2SO4 + 8 KI = H2S + 4 H2O + 8 I + 8 KHSO4
KCO2 + Sn3(PO4)4 = K3PO4 + Sn(C2O4)2 =>
12 KCO2 + Sn3(PO4)4 = 4 K3PO4 + 3 Sn(C2O4)2
Cl2 + Al(OH)3 = Al(ClO)3 + AlCl3 + H2O =>
3 Cl2 + 2 Al(OH)3 = Al(ClO)3 + AlCl3 + 3 H2O
Br + HCl = HBr + Cl =>
Br + HCl = HBr + Cl
HCHO + KMnO4 + H2SO4 = HCOOH + K2SO4 + MnO2 + H2O =>
3 HCHO + 2 KMnO4 + H2SO4 = 3 HCOOH + K2SO4 + 2 MnO2 + H2O
Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl
K3[Cr(C2O4)3]3H2O + KMnO4 + H2SO4 = Cr(SO4)3 + MnSO4 + K2SO4 + CO2 + H2O =>
5 K3[Cr(C2O4)3]3H2O + 21 KMnO4 + 84 H2SO4 = 15 Cr(SO4)3 + 21 MnSO4 + 18 K2SO4 + 90 CO2 + 89 H2O
Na2S + Ag + O2 + H2O = Ag2S + NaOH =>
2 Na2S + 4 Ag + O2 + 2 H2O = 2 Ag2S + 4 NaOH
KMnO4 + Na2C2O4 + H2SO4 = K2SO4 + CO2 + MnSO4 + Na2SO4 + H2O =>
2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 = K2SO4 + 10 CO2 + 2 MnSO4 + 5 Na2SO4 + 8 H2O
Fe + K3[Fe(CN)6] = Fe4[Fe(CN)6]3 + K =>
4 Fe + 3 K3[Fe(CN)6] = Fe4[Fe(CN)6]3 + 9 K
CH3CH4 + O2 = CO2 + H2O =>
4 CH3CH4 + 15 O2 = 8 CO2 + 14 H2O
Ag + He2 = AgHe3 =>
2 Ag + 3 He2 = 2 AgHe3
HCOOH + NH3 = HCOON + H =>
HCOOH + NH3 = HCOON + 4 H
Mg(OH)2 + HCl = MgCl2 + H2O =>
Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O
C6H5NO2 + Zn + KOH + H2O = C6H5NH2 + K2[Zn(OH)4] =>
C6H5NO2 + 3 Zn + 6 KOH + 4 H2O = C6H5NH2 + 3 K2[Zn(OH)4]
HI + (NH4)2SO3 = H2SO3 + NH4I =>
2 HI + (NH4)2SO3 = H2SO3 + 2 NH4I
KCl*NaCl = KCl + NaCl =>
KCl*NaCl = KCl + NaCl
HCl + LiCH3 = LiCl + CH4 =>
HCl + LiCH3 = LiCl + CH4
Fe(OH)3 + HCl = FeCl3 + H2O =>
Fe(OH)3 + 3 HCl = FeCl3 + 3 H2O
Hg(NO3)2 + Al = Al(NO3)3 + Hg2 =>
6 Hg(NO3)2 + 4 Al = 4 Al(NO3)3 + 3 Hg2
Ni(OH)4 + HNO3 = Ni(NO3)4 + H2O =>
Ni(OH)4 + 4 HNO3 = Ni(NO3)4 + 4 H2O
Ba + Cu2O = BaO + Cu =>
Ba + Cu2O = BaO + 2 Cu
Na2MnO4 + FeBr + HBr = NaBr + MnBr2 + FeBr3 + H2O =>
Na2MnO4 + 2 FeBr + 8 HBr = 2 NaBr + MnBr2 + 2 FeBr3 + 4 H2O
NaClO + H2O = HClO + NaOH =>
NaClO + H2O = HClO + NaOH
K3PO4 + MgSO4 = K2SO4 + Mg3(PO4)2 =>
2 K3PO4 + 3 MgSO4 = 3 K2SO4 + Mg3(PO4)2
H3PO4(aq)Sr(OH)2(aq) = H3(OH)2SrPO4 =>
H3PO4(aq)Sr(OH)2(aq) = H3(OH)2SrPO4
Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O
CH3OH(l) + Na(s) = NaOCH3(s) + H2(g) =>
2 CH3OH(l) + 2 Na(s) = 2 NaOCH3(s) + H2(g)
H2SO4 + AgCl + Ag2Cr2O7 = Cr2(SO4) + Ag2SO4 + Cl2 + H2O =>
7 H2SO4 + 10 AgCl + Ag2Cr2O7 = Cr2(SO4) + 6 Ag2SO4 + 5 Cl2 + 7 H2O
KHSO3 + CaO = CaSO3 + KOH =>
KHSO3 + CaO = CaSO3 + KOH
C6H5OH + NH3 = C6H5NH2 + NH4OH =>
C6H5OH + 2 NH3 = C6H5NH2 + NH4OH
PCl5 = PCl2 + Cl2 =>
2 PCl5 = 2 PCl2 + 3 Cl2
TiCl4 + Mg = Ti2 + MgCl =>
2 TiCl4 + 8 Mg = Ti2 + 8 MgCl
Mg + HCl = MgCl2 + H2 =>
Mg + 2 HCl = MgCl2 + H2
K3PO4 + MgSO4 = K2SO4 + Mg3(PO4)2 =>
2 K3PO4 + 3 MgSO4 = 3 K2SO4 + Mg3(PO4)2
Ba + CH3COOH = H2 + CBa2COOH =>
4 Ba + 2 CH3COOH = 3 H2 + 2 CBa2COOH
Cu(NO3)2 + K2CrO4 = CuCrO4 + KNO3 =>
Cu(NO3)2 + K2CrO4 = CuCrO4 + 2 KNO3
N + H2O = NO2 + NH3 =>
7 N + 6 H2O = 3 NO2 + 4 NH3
K2CrO7 + HCl = KCl + CrCl3 + O2 + H2O =>
4 K2CrO7 + 20 HCl = 8 KCl + 4 CrCl3 + 9 O2 + 10 H2O
C4H9OH + KMnO4 + H2O = C3H7(OH)2 + KOH + MnO =>
15 C4H9OH + 4 KMnO4 + 17 H2O = 20 C3H7(OH)2 + 4 KOH + 4 MnO
HCHO + [Ag(NH3)2]OH = (NH)2CO3 + Ag + NH3 + H2O =>
HCHO + 10[Ag(NH3)2]OH = (NH)2CO3 + 10 Ag + 18 NH3 + 8 H2O
C6H6 + O2 = CO2 + H2O =>
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
Ag + H2C + O2 = AgC + H2O =>
2 Ag + 2 H2C + O2 = 2 AgC + 2 H2O
Pb(NO3)2 + K2C2O4 = PbC2O4 + KNO3 =>
Pb(NO3)2 + K2C2O4 = PbC2O4 + 2 KNO3
TiO(OH)2 + Na2SO4 = TiO(SO4) + NaOH =>
TiO(OH)2 + Na2SO4 = TiO(SO4) + 2 NaOH
Rb2O + SO3 = Rb2O3 + SO2 =>
Rb2O + 2 SO3 = Rb2O3 + 2 SO2
Al + HCl = (H)2 + Al(Cl)3 =>
2 Al + 6 HCl = 3(H)2 + 2 Al(Cl)3
K3PO4 + SrCl2 = KCl + Sr3(PO4)2 =>
2 K3PO4 + 3 SrCl2 = 6 KCl + Sr3(PO4)2
HC3H5O3 + NaOH = NaC3H5O3 + H2O =>
HC3H5O3 + NaOH = NaC3H5O3 + H2O
HBrO + NaOH = NaO + HBrOH =>
HBrO + NaOH = NaO + HBrOH
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/12/24
Equations balanced on 03/13/23
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