Equations balanced on the previous day | Equations balanced on the next day |
2 HBr(aq) + K2S(s) = H2S(aq) + 2 KBr(aq)
K + MgO = Mg + KO =>
K + MgO = Mg + KO
C + H = CH =>
C + H = CH
I{-} + H2O2 + H3O{+} = I3{-} + H2O =>
3 I{-} + H2O2 + 2 H3O{+} = I3{-} + 4 H2O
MnO4{-} + ClO3{-} + H3O{+} = Mn2{+} + ClO4{-} + H2O =>
4 MnO4{-} + 13 ClO3{-} + 6 H3O{+} = 2 Mn2{+} + 13 ClO4{-} + 9 H2O
Ca + CuBr = CaBr2 + Cu =>
Ca + 2 CuBr = CaBr2 + 2 Cu
K2Cr2O7 + C3H6 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3COOH + H2O =>
2 K2Cr2O7 + 2 C3H6 + 8 H2SO4 = 2 Cr2(SO4)3 + 2 K2SO4 + 3 CH3COOH + 8 H2O
I{-} + IO3{-} + H{+} = I3{-} + H2O =>
8 I{-} + IO3{-} + 6 H{+} = 3 I3{-} + 3 H2O
K + MgO = Mg + KO =>
K + MgO = Mg + KO
Ba + HBr(l) = BaBr + H =>
Ba + HBr(l) = BaBr + H
LiOH + BeO + H2O = Li2[Be(OH)4] =>
2 LiOH + BeO + H2O = Li2[Be(OH)4]
NaSO4 + NaClO4 + NaI + H2O = SCl2 + NaOH + I2 =>
2 NaSO4 + 4 NaClO4 + 42 NaI + 24 H2O = 2 SCl2 + 48 NaOH + 21 I2
O2 + MnSO4 + NaOH + H2O = Mn(OH)3 + Na2SO4 =>
O2 + 4 MnSO4 + 8 NaOH + 2 H2O = 4 Mn(OH)3 + 4 Na2SO4
C6H6O + C4H6O3 = C8H8O2 + H2O =>
2 C6H6O + C4H6O3 = 2 C8H8O2 + H2O
UCl4 + O2 + H2O = UO2Cl2 + HClO2 =>
2 UCl4 + 5 O2 + 2 H2O = 2 UO2Cl2 + 4 HClO2
NH*H*H + O*O = NO + H*HO =>
4 NH*H*H + 5 O*O = 4 NO + 6 H*HO
Mg + H2O = Mg(H2O)2 =>
Mg + 2 H2O = Mg(H2O)2
CH3COOH + NH4OH = H2O + NH4 + CH3COOO =>
CH3COOH + 3 NH4OH = 2 H2O + 3 NH4 + CH3COOO
Co2 + KCl3 + KOH = Co2O3 + KCl + H2O =>
Co2 + 3 KCl3 + 6 KOH = Co2O3 + 9 KCl + 3 H2O
Po(OH)4 + HCl = PoCl4 + H2O =>
Po(OH)4 + 4 HCl = PoCl4 + 4 H2O
Ba + HBr(l) = BaBr + H =>
Ba + HBr(l) = BaBr + H
NaHCO3(s) + HC2H3O2(aq) = CO2(g) + H2O(l) + NaC2H3O2(aq) =>
NaHCO3(s) + HC2H3O2(aq) = CO2(g) + H2O(l) + NaC2H3O2(aq)
UCl4 + O2 + H2O = UO2Cl2 + HClO2 =>
2 UCl4 + 5 O2 + 2 H2O = 2 UO2Cl2 + 4 HClO2
Cl2H2C + Cl2 = Cl3HC + HCl =>
Cl2H2C + Cl2 = Cl3HC + HCl
KCrO2 + HCl + H2O = CrCl3*(H2O)6 + KCl =>
KCrO2 + 4 HCl + 4 H2O = CrCl3*(H2O)6 + KCl
H2O + O = H2OHO =>
3 H2O + O = 2 H2OHO
C6H6O + C4H6O3 = C8H8O2 + H2O =>
2 C6H6O + C4H6O3 = 2 C8H8O2 + H2O
C17H2NO4 + O2 = CO2 + H2O + N2 =>
2 C17H2NO4 + 31 O2 = 34 CO2 + 2 H2O + N2
K2Cr2O7 + C3H6 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3COOH + H2O =>
2 K2Cr2O7 + 2 C3H6 + 8 H2SO4 = 2 Cr2(SO4)3 + 2 K2SO4 + 3 CH3COOH + 8 H2O
BaO2 + HCl = BaCl2 + H2O2 =>
BaO2 + 2 HCl = BaCl2 + H2O2
O + H2O = OH =>
O + H2O = 2 OH
Hg + H2O = Hg(OH)2 + H3O =>
Hg + 4 H2O = Hg(OH)2 + 2 H3O
C3H6 + K2Cr2O7 + H2SO4 = C3H6(OH)2 + K2SO4 + Cr2(SO4)3 + H2O =>
3 C3H6 + K2Cr2O7 + 4 H2SO4 = 3 C3H6(OH)2 + K2SO4 + Cr2(SO4)3 + H2O
FeSO4 = Fe{3+} + SO4{2-} + e =>
FeSO4 = Fe{3+} + SO4{2-} + e
Na2CO3 + HCl = NaCl + H2O + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
UCl4 + O2 + H2O = UO2Cl2 + HCl =>
2 UCl4 + O2 + 2 H2O = 2 UO2Cl2 + 4 HCl
NaCH3CO2 + HI = NaI + CH3CO2H =>
NaCH3CO2 + HI = NaI + CH3CO2H
HCl(aq) + O2(g) = H2O(l) + Cl2(g) = HCI + O2 = H2O + CI2 =>
4 HCl(aq) + O2(g) = 2 H2O(l) + 2 Cl2(g)
KNO3 + Al + KOH + H2O = KAl(OH)4 + NH4OH =>
3 KNO3 + 8 Al + 5 KOH + 21 H2O = 8 KAl(OH)4 + 3 NH4OH
UCl4 + O2 + H2O = UO2Cl2 + HClO =>
2 UCl4 + 3 O2 + 2 H2O = 2 UO2Cl2 + 4 HClO
Ba + HBr(l) = BaBr + H =>
Ba + HBr(l) = BaBr + H
C6H6O + C4H6O3 = C8H8O2 + H2O =>
2 C6H6O + C4H6O3 = 2 C8H8O2 + H2O
K + MgO = Mg + KO =>
K + MgO = Mg + KO
Zn + H2PO4{-} + H3O{+} = Zn{2+} + PH3 + H2O =>
4 Zn + H2PO4{-} + 9 H3O{+} = 4 Zn{2+} + PH3 + 13 H2O
SiC + F2 = CF4 + SiF4 =>
SiC + 4 F2 = CF4 + SiF4
Ca + CuBr = CaBr2 + Cu =>
Ca + 2 CuBr = CaBr2 + 2 Cu
K2Cr2O7 + C3H6 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3COOH + H2O =>
2 K2Cr2O7 + 2 C3H6 + 8 H2SO4 = 2 Cr2(SO4)3 + 2 K2SO4 + 3 CH3COOH + 8 H2O
UCl4 + O2 + H2O = UO2Cl2 + HClO2 =>
2 UCl4 + 5 O2 + 2 H2O = 2 UO2Cl2 + 4 HClO2
UCl4 + O2 + H2O = UO2Cl2 + HClO2 =>
2 UCl4 + 5 O2 + 2 H2O = 2 UO2Cl2 + 4 HClO2
H2O + O = H2OHO =>
3 H2O + O = 2 H2OHO
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/04/24
Equations balanced on 02/03/23
저희 화학반응식 계산기에 만족하셨다면 만족도 평가를 남겨주세요