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화학 방정식은 다음에 대해 균형을 이룹니다.12/21/23

 전날에 균형이 맞춰진 방정식 다음 날에 균형을 이룬 방정식
모든 화학 반응의 방정식을 균형화합니다
HNO3(aq) + K2SO3(aq) = HSO3(s) + K2NO3(s) =>
HNO3(aq) + K2SO3(aq) = HSO3(s) + K2NO3(s)

C7H16 + O2 = CO2 + H2 =>
C7H16 + 7 O2 = 7 CO2 + 8 H2

PH3 + O2 = H2O + P4O10 =>
4 PH3 + 8 O2 = 6 H2O + P4O10

SO2 + Pb(NO3)2 = PbSO3 + N2O5 =>
SO2 + Pb(NO3)2 = PbSO3 + N2O5

HCl(aq) + Zn = ZnCl + H(g) =>
HCl(aq) + Zn = ZnCl + H(g)

H2CO2 + Ba(OH)2 = BaCO2 + H2O =>
H2CO2 + Ba(OH)2 = BaCO2 + 2 H2O

Fe + O2 + H2O = Fe2O3(HO) =>
8 Fe + 7 O2 + 2 H2O = 4 Fe2O3(HO)

NaCl + F2 = Cl + NaF =>
2 NaCl + F2 = 2 Cl + 2 NaF

S{2-} + I2 + H2O = SO4{2-} + I{-} + H{+} =>
S{2-} + 4 I2 + 4 H2O = SO4{2-} + 8 I{-} + 8 H{+}

Mn2O7 + K2SO4 + H2O = KMnO4 + H2SO4 =>
Mn2O7 + K2SO4 + H2O = 2 KMnO4 + H2SO4

NH3H2O + HNO3 = NH4(NO3)2 + H2O =>
7 NH3H2O + 17 HNO3 = 8 NH4(NO3)2 + 10 H2O

Ba + SO4 = BaSO4 =>
Ba + SO4 = BaSO4

CH3COOH + NaNO2 = CH3COONa + NO2 + NO + H2O =>
2 CH3COOH + 2 NaNO2 = 2 CH3COONa + NO2 + NO + H2O

Fe3No3 + LiOH = LiNo3 + Fe3OH =>
Fe3No3 + LiOH = LiNo3 + Fe3OH

C7H15COOH + Fe(OH)3 = (C7H15COO)3Fe + H2O =>
3 C7H15COOH + Fe(OH)3 = (C7H15COO)3Fe + 3 H2O

Cl2(g) + NaBr(s) = Br2(g) + NaCl =>
Cl2(g) + 2 NaBr(s) = Br2(g) + 2 NaCl

Fe + K3[Fe(CN)6] = Fe3[Fe(CN)6]2 + K =>
3 Fe + 2 K3[Fe(CN)6] = Fe3[Fe(CN)6]2 + 6 K

NH4OH + H2SO4 = NH4H2 + SO4OH =>
NH4OH + H2SO4 = NH4H2 + SO4OH

Ba(ClO3)2 + Na2SO4 = BaSO4 + NaClO3 =>
Ba(ClO3)2 + Na2SO4 = BaSO4 + 2 NaClO3

CrO3 + NaHSO3 + H2O = Cr(OH)2 + Na2SO4 + H2SO4 =>
CrO3 + 2 NaHSO3 + H2O = Cr(OH)2 + Na2SO4 + H2SO4

C8H168(l) + O2(g) = CO2(g) + H2O(l) =>
C8H168(l) + 50 O2(g) = 8 CO2(g) + 84 H2O(l)

Sr2 + CuCl = Cl2Sr + Cu =>
Sr2 + 4 CuCl = 2 Cl2Sr + 4 Cu

C3H5N3O9 = N2 + C02 + O2 + H2O =>
4 C3H5N3O9 = 6 N2 + 6 C02 + 13 O2 + 10 H2O

C4H10 + O2 = CO6 + OH12 =>
12 C4H10 + 149 O2 = 48 CO6 + 10 OH12

NaS + H2SO4 = H2S + NaSO =>
4 NaS + H2SO4 = H2S + 4 NaSO

NaOH + Zn + H2O + KNO3 = K2[Zn(OH)4] + Na[Zn(HO)4] + NH3 =>
14 NaOH + 17 Zn + 36 H2O + 6 KNO3 = 3 K2[Zn(OH)4] + 14 Na[Zn(HO)4] + 6 NH3

Si3N4 + NF3 + H2 = SiF4 + NH3 =>
Si3N4 + 4 NF3 + 12 H2 = 3 SiF4 + 8 NH3

Ca3[PO4]2 + SiO2 + C = CaSiO3 + CO + P =>
Ca3[PO4]2 + 3 SiO2 + 5 C = 3 CaSiO3 + 5 CO + 2 P

K2Cr2O7 + HCl + NaHSO3 = H2O + CrCl3 + KCl + NaHSO4 =>
K2Cr2O7 + 8 HCl + 3 NaHSO3 = 4 H2O + 2 CrCl3 + 2 KCl + 3 NaHSO4

NaF + KNo3 = NaNo3 + KF =>
NaF + KNo3 = NaNo3 + KF

Cr(NO3)3 = Cr2O3 + NO2 + O2 =>
4 Cr(NO3)3 = 2 Cr2O3 + 12 NO2 + 3 O2

NiS + HNO3 = H2O + NO2 + Ni(NO3)2 + SO2 =>
NiS + 8 HNO3 = 4 H2O + 6 NO2 + Ni(NO3)2 + SO2

VCl2 + K2Cr2O7 + H2O = Cr(OH)3 + VOCl2 + KOH =>
3 VCl2 + K2Cr2O7 + 4 H2O = 2 Cr(OH)3 + 3 VOCl2 + 2 KOH

C8H15Cl3 + AgNO3 = AgCl + C8H15 + NO3 =>
C8H15Cl3 + 3 AgNO3 = 3 AgCl + C8H15 + 3 NO3

RuCl3H2O + PPh3 + CH2O = [Ru(PPh3)3H(CO)Cl] + OPPh3 + HCl + H2O =>
2 RuCl3H2O + 7 PPh3 + 2 CH2O = 2[Ru(PPh3)3H(CO)Cl] + OPPh3 + 4 HCl + H2O

Na + C + O2 = Na2CO3 =>
4 Na + 2 C + 3 O2 = 2 Na2CO3

Mn2(CO3)7 + HBr = MnBr7 + CO2 + H2O =>
Mn2(CO3)7 + 14 HBr = 2 MnBr7 + 7 CO2 + 7 H2O

ZnBr2(aq) + KCl(aq) = KBr + ZnCl2 =>
ZnBr2(aq) + 2 KCl(aq) = 2 KBr + ZnCl2

Bi(NO3)3*5H2O + Fe(NO3)3*9H2O + Y(NO3)3*6H2O + Cu(NO3)3*3H2O + C6H8O7 = Bi95Y5Fe75Cu25O300 + CO2 + H2O + N2 =>
285 Bi(NO3)3*5H2O + 225 Fe(NO3)3*9H2O + 15 Y(NO3)3*6H2O + 75 Cu(NO3)3*3H2O + 500 C6H8O7 = 3 Bi95Y5Fe75Cu25O300 + 3000 CO2 + 5765 H2O + 900 N2

CH3CH(NH2)CH2CH3HCl = CH3CH(NH3)CH2CH3Cl =>
CH3CH(NH2)CH2CH3HCl = CH3CH(NH3)CH2CH3Cl

HNo3 + Ba(OH)2 = Ba(No3)2 + H2O =>
2 HNo3 + Ba(OH)2 = Ba(No3)2 + 2 H2O

CoSO4 + Fe = Fe(SO4)3 + Co =>
3 CoSO4 + Fe = Fe(SO4)3 + 3 Co

As2O2 + HNO3 + H2O = H3AsO4 + NO =>
As2O2 + 2 HNO3 + 2 H2O = 2 H3AsO4 + 2 NO

Au8S3 + H2 = Au + H2S =>
Au8S3 + 3 H2 = 8 Au + 3 H2S

[Fe(C2O4)3] + NH3 + H2O = Fe2O3 + NH4 + C2O4 =>
2[Fe(C2O4)3] + 6 NH3 + 3 H2O = Fe2O3 + 6 NH4 + 6 C2O4

C8H18(l) + O2(g) = CO2(g) + H2O(g) =>
2 C8H18(l) + 25 O2(g) = 16 CO2(g) + 18 H2O(g)

Mg + CO2H2O2 = MgO + C + H2O =>
3 Mg + CO2H2O2 = 3 MgO + C + H2O

O2(g) + C12H22O11(s) = H2O(l) + CO2(g) =>
12 O2(g) + C12H22O11(s) = 11 H2O(l) + 12 CO2(g)

N2H4 + H2Cr2O7 = N2 + Cr2O3 + H2O =>
3 N2H4 + 2 H2Cr2O7 = 3 N2 + 2 Cr2O3 + 8 H2O

SnCl4 + NaI = I2 + SnI3 + NaCl =>
2 SnCl4 + 8 NaI = I2 + 2 SnI3 + 8 NaCl

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모든 화학 반응의 방정식을 균형화합니다
 전날에 균형이 맞춰진 방정식 다음 날에 균형을 이룬 방정식
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