Equations balanced on the previous day | Equations balanced on the next day |
2 H2 + O2 = 2 H2O
BaCl2 + Al2(CO3)3 = BaCO3 + AlCl3 =>
3 BaCl2 + Al2(CO3)3 = 3 BaCO3 + 2 AlCl3
BaCl2 + Al2(CO3)3 = BaCO3 + AlCl3 =>
3 BaCl2 + Al2(CO3)3 = 3 BaCO3 + 2 AlCl3
KCl + Pb = PbCl2 + K =>
2 KCl + Pb = PbCl2 + 2 K
BaCl2 + Al2(CO3)3 = BaCO3 + AlCl3 =>
3 BaCl2 + Al2(CO3)3 = 3 BaCO3 + 2 AlCl3
S1 + H2 = HS =>
2 S1 + H2 = 2 HS
Bi(NO3)3 + SnCl2 + KOH = Bi + K2[Sn(OH)6] + KNO3 + KCl =>
2 Bi(NO3)3 + 3 SnCl2 + 18 KOH = 2 Bi + 3 K2[Sn(OH)6] + 6 KNO3 + 6 KCl
Ba(BrF4)2 + RbBrF4 = BaRbBr3F10 + F2 =>
Ba(BrF4)2 + RbBrF4 = BaRbBr3F10 + F2
(Y)2S + Co(X)2 = CoS + YX =>
(Y)2S + Co(X)2 = CoS + 2 YX
Mn + HO = MnOH =>
Mn + HO = MnOH
(C3H3NO2)CH2COOH + NH2CH(CH2C6H5)COOCH3 = C14H17N2O5 + CH2O =>
(C3H3NO2)CH2COOH + NH2CH(CH2C6H5)COOCH3 = C14H17N2O5 + CH2O
Bi(NO3)3 + SnCl2 + KOH = Bi + K2[Sn(OH)6] + KNO3 + KCl =>
2 Bi(NO3)3 + 3 SnCl2 + 18 KOH = 2 Bi + 3 K2[Sn(OH)6] + 6 KNO3 + 6 KCl
Na + Cl = NaCl =>
Na + Cl = NaCl
HNO3 + SrCO3 = Sr(NO3)2 + H2O + CO2 =>
2 HNO3 + SrCO3 = Sr(NO3)2 + H2O + CO2
K(s) + H2O(l) = KOH(aq) + H2(g) =>
2 K(s) + 2 H2O(l) = 2 KOH(aq) + H2(g)
Bi(NO3)3 + SnCl2 + KOH = Bi + K2[Sn(OH)6] + KNO3 + KCl =>
2 Bi(NO3)3 + 3 SnCl2 + 18 KOH = 2 Bi + 3 K2[Sn(OH)6] + 6 KNO3 + 6 KCl
Na2HPO4 + (NH4)2MoO4 + HNO3 = (NH4)3(PO5*12MoO3) + NH4NO3 + NaNO3 + H2O =>
4 Na2HPO4 + 48(NH4)2MoO4 + 94 HNO3 = 4(NH4)3(PO5*12MoO3) + 85 NH4NO3 + 8 NaNO3 + 47 H2O
[Cu(NH3)4] + H2O2 = CuO + NH3 + H2 =>
2[Cu(NH3)4] + H2O2 = 2 CuO + 8 NH3 + H2
Al2(NO3)3 + Na2S = Al2S3 + Na2NO3 =>
Al2(NO3)3 + 3 Na2S = Al2S3 + 3 Na2NO3
N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3
[Cu(NH3)4] + H2O2 = CuO + NH3 + H2 =>
2[Cu(NH3)4] + H2O2 = 2 CuO + 8 NH3 + H2
Bi(NO3)3 + SnCl2 + KOH = Bi + K2[Sn(OH)6] + KNO3 + KCl =>
2 Bi(NO3)3 + 3 SnCl2 + 18 KOH = 2 Bi + 3 K2[Sn(OH)6] + 6 KNO3 + 6 KCl
BeI2 + O3 + H2O = HIO3 + BeO =>
BeI2 + 2 O3 + H2O = 2 HIO3 + BeO
K2Zn(OH)4 + HCl = KCl + Zn(OH)2 + H2O =>
K2Zn(OH)4 + 2 HCl = 2 KCl + Zn(OH)2 + 2 H2O
Al(NO3)3 + NaOH = Al(OH)3 + NaNO3 =>
Al(NO3)3 + 3 NaOH = Al(OH)3 + 3 NaNO3
HNO3 + KOH = KNO3 + H2O =>
HNO3 + KOH = KNO3 + H2O
NH4OH + Cl2 = NH4Cl + H2O2 =>
2 NH4OH + Cl2 = 2 NH4Cl + H2O2
KMnO4 + SnCl2 + H2SO4 = MnSO4 + SnCl4 + Sn(SO4)2 + K2SO4 + H2O =>
4 KMnO4 + 10 SnCl2 + 16 H2SO4 = 4 MnSO4 + 5 SnCl4 + 5 Sn(SO4)2 + 2 K2SO4 + 16 H2O
Se(Cl6) + O2 = Se(O2) + Cl2 =>
Se(Cl6) + O2 = Se(O2) + 3 Cl2
NaI + Cd = NaCd + I2 =>
2 NaI + 2 Cd = 2 NaCd + I2
Na2CO3 + NaBr = Br2CO3 + Na =>
Na2CO3 + 2 NaBr = Br2CO3 + 4 Na
NaI + Pb(C2H3O2) = NaPb + IC2H3O2 =>
NaI + Pb(C2H3O2) = NaPb + IC2H3O2
MnO4{-} + H{+} + H2C2O4 = Mn2{+} + CO2 + H2O =>
4 MnO4{-} + 6 H{+} + 13 H2C2O4 = 2 Mn2{+} + 26 CO2 + 16 H2O
Rb + Br2 = RbBr =>
2 Rb + Br2 = 2 RbBr
KMnO4 + SnCl2 + H2SO4 = MnSO4 + SnCl4 + Sn(SO4)2 + K2SO4 + H2O =>
4 KMnO4 + 10 SnCl2 + 16 H2SO4 = 4 MnSO4 + 5 SnCl4 + 5 Sn(SO4)2 + 2 K2SO4 + 16 H2O
KMnO4 + SnCl2 + H2SO4 = MnSO4 + SnCl4 + Sn(SO4)2 + K2SO4 + H2O =>
4 KMnO4 + 10 SnCl2 + 16 H2SO4 = 4 MnSO4 + 5 SnCl4 + 5 Sn(SO4)2 + 2 K2SO4 + 16 H2O
PbO2 + HNO3 = Pb(NO3)2 + H2 + O =>
PbO2 + 2 HNO3 = Pb(NO3)2 + H2 + 2 O
FeS04 + O2 = Fe2 + SO4 =>
2 FeS04 + 16 O2 = Fe2 + 8 SO4
K + CaBr2 = KBr + Ca =>
2 K + CaBr2 = 2 KBr + Ca
KMnO4 + SnCl2 + H2SO4 = MnSO4 + SnCl4 + Sn(SO4)2 + K2SO4 + H2O =>
4 KMnO4 + 10 SnCl2 + 16 H2SO4 = 4 MnSO4 + 5 SnCl4 + 5 Sn(SO4)2 + 2 K2SO4 + 16 H2O
BaSO4 + KNO3 = Ba(NO3)2 + K2SO4 =>
BaSO4 + 2 KNO3 = Ba(NO3)2 + K2SO4
K(MnO4) + ZnCl2 = KCl + Zn1(MnO4)2 =>
2 K(MnO4) + ZnCl2 = 2 KCl + Zn1(MnO4)2
Na2C204 + KMnO4 + H2SO4 = K2SO4 + Na2SO4 + MnSO4 + CO2 + H2O =>
5 Na2C204 + 818 KMnO4 + 1232 H2SO4 = 409 K2SO4 + 5 Na2SO4 + 818 MnSO4 + 1020 CO2 + 1232 H2O
BeI2 + O3 + H2O = HIO3 + BeO2 =>
3 BeI2 + 7 O3 + 3 H2O = 6 HIO3 + 3 BeO2
Cu(NO3)2 = CuO + NO2 + O2 =>
2 Cu(NO3)2 = 2 CuO + 4 NO2 + O2
Na2C204 + KMnO4 + H2SO4 = K2SO4 + Na2SO4 + MnSO4 + CO2 + H2O =>
5 Na2C204 + 818 KMnO4 + 1232 H2SO4 = 409 K2SO4 + 5 Na2SO4 + 818 MnSO4 + 1020 CO2 + 1232 H2O
K + CaBr2 = KBr + Ca =>
2 K + CaBr2 = 2 KBr + Ca
KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2
A3 = A4 =>
4 A3 = 3 A4
NaH2PO4 + Ba(OH)2 = BaH2PO4 + Na(OH)2 =>
NaH2PO4 + Ba(OH)2 = BaH2PO4 + Na(OH)2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/17/23
Equations balanced on 12/17/22
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